15r2-7-5r(3r+4)=3(7-4r)

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Solution for 15r2-7-5r(3r+4)=3(7-4r) equation: 



15r^2-7-5r(3r+4)=3(7-4r)

We move all terms to the left:

15r^2-7-5r(3r+4)-(3(7-4r))=0

We add all the numbers together, and all the variables

15r^2-5r(3r+4)-(3(-4r+7))-7=0

We multiply parentheses

15r^2-15r^2-20r-(3(-4r+7))-7=0



We calculate terms in parentheses: -(3(-4r+7)), so:

3(-4r+7)

We multiply parentheses

-12r+21

Back to the equation:

-(-12r+21)



We add all the numbers together, and all the variables

-20r-(-12r+21)-7=0

We get rid of parentheses

-20r+12r-21-7=0

We add all the numbers together, and all the variables

-8r-28=0

We move all terms containing r to the left, all other terms to the right

-8r=28

r=28/-8

r=-3+1/2

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