15t=18(t-1/2)

Solution for 15t=18(t-1/2) equation:

15t=18(t-1/2)

We move all terms to the left:

15t-(18(t-1/2))=0

We add all the numbers together, and all the variables

15t-(18(+t-1/2))=0

We multiply all the terms by the denominator


15t*2))-(18(+t-1=0

We add all the numbers together, and all the variables

t+15t*2))-(18(-1=0

Wy multiply elements

30t^2+t-1=0

a = 30; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·30·(-1)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-11}{2*30}=\frac{-12}{60}
=-1/5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+11}{2*30}=\frac{10}{60}
=1/6
$