15t=t2

Solution for 15t=t2 equation:

15t=t2

We move all terms to the left:

15t-(t2)=0

We add all the numbers together, and all the variables

-1t^2+15t=0

a = -1; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-1)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-1}=\frac{-30}{-2}
=+15
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-1}=\frac{0}{-2}
=0
$