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15u^2+80u+65=0
a = 15; b = 80; c = +65;
Δ = b2-4ac
Δ = 802-4·15·65
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-50}{2*15}=\frac{-130}{30} =-4+1/3 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+50}{2*15}=\frac{-30}{30} =-1 $
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