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15x(13x+5)=120
We move all terms to the left:
15x(13x+5)-(120)=0
We multiply parentheses
195x^2+75x-120=0
a = 195; b = 75; c = -120;
Δ = b2-4ac
Δ = 752-4·195·(-120)
Δ = 99225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{99225}=315$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-315}{2*195}=\frac{-390}{390} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+315}{2*195}=\frac{240}{390} =8/13 $
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