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15x+17x-3x(x=3)
We move all terms to the left:
15x+17x-3x(x-(3))=0
We add all the numbers together, and all the variables
32x-3x(x-3)=0
We multiply parentheses
-3x^2+32x+9x=0
We add all the numbers together, and all the variables
-3x^2+41x=0
a = -3; b = 41; c = 0;
Δ = b2-4ac
Δ = 412-4·(-3)·0
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-41}{2*-3}=\frac{-82}{-6} =13+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+41}{2*-3}=\frac{0}{-6} =0 $
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