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15x-11=6x+2(3x-3)
We move all terms to the left:
15x-11-(6x+2(3x-3))=0
We calculate terms in parentheses: -(6x+2(3x-3)), so:We get rid of parentheses
6x+2(3x-3)
We multiply parentheses
6x+6x-6
We add all the numbers together, and all the variables
12x-6
Back to the equation:
-(12x-6)
15x-12x+6-11=0
We add all the numbers together, and all the variables
3x-5=0
We move all terms containing x to the left, all other terms to the right
3x=5
x=5/3
x=1+2/3
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