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15x-19=5(2x-4)+5x+1
We move all terms to the left:
15x-19-(5(2x-4)+5x+1)=0
We calculate terms in parentheses: -(5(2x-4)+5x+1), so:We get rid of parentheses
5(2x-4)+5x+1
We add all the numbers together, and all the variables
5x+5(2x-4)+1
We multiply parentheses
5x+10x-20+1
We add all the numbers together, and all the variables
15x-19
Back to the equation:
-(15x-19)
15x-15x+19-19=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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