15x-2=(3x+2)+(16)

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Solution for 15x-2=(3x+2)+(16) equation: 



15x-2=(3x+2)+(16)

We move all terms to the left:

15x-2-((3x+2)+(16))=0



We calculate terms in parentheses: -((3x+2)+16), so:

(3x+2)+16

We get rid of parentheses

3x+2+16

We add all the numbers together, and all the variables

3x+18

Back to the equation:

-(3x+18)



We get rid of parentheses

15x-3x-18-2=0

We add all the numbers together, and all the variables

12x-20=0

We move all terms containing x to the left, all other terms to the right

12x=20

x=20/12

x=1+2/3

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