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15x-3-4(x-1)=2(x+3)+13
We move all terms to the left:
15x-3-4(x-1)-(2(x+3)+13)=0
We multiply parentheses
15x-4x-(2(x+3)+13)+4-3=0
We calculate terms in parentheses: -(2(x+3)+13), so:We add all the numbers together, and all the variables
2(x+3)+13
We multiply parentheses
2x+6+13
We add all the numbers together, and all the variables
2x+19
Back to the equation:
-(2x+19)
11x-(2x+19)+1=0
We get rid of parentheses
11x-2x-19+1=0
We add all the numbers together, and all the variables
9x-18=0
We move all terms containing x to the left, all other terms to the right
9x=18
x=18/9
x=2
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