If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/x+1
1*x^3-(5*x^2)-(5*x)+25 = 3;x
x
sin(x)*ln(2*x)
1*x^3-(5*x^2)-(5*x)+25 = 0;x
x
12-(-216/(-8))+3+2
| 6/2-4/3= | | (X)+(4x-10)=180 | | 12-9x=-24 | | 3x+26-2x=-6 | | 2c=5c+5 | | 7(2x-1)-3(2a-b)= | | (5x)+(3x+12)=90 | | 2x-y+x+y=360 | | 6x-16=-34 | | 120+60+x+y=360 | | 2-(-216/(-8)-3-12) | | 60+120+x+y+60=360 | | 1.5(22-x)(22/2-x/2) | | 60+120+2x-y+60=360 | | (15x+5y+10)+(8y+6x-9)= | | (2x+21)+(3x-4)=90 | | 2/3=34z | | 2/3=z34 | | 10-5x=26-7x | | 0.04(y-1)+0.16y=0.08y-0.07(10) | | 10x-5y=2x-3y | | 0.20x+0.45(70)=32.5 | | 64=y-48 | | 24=r+15 | | 39(y-3)=6y | | (n/-7)-2=10 | | 4x-3(5x-2)=6(2x+7)-7 | | 2x-y+60=x+y+60 | | -6u+30=4u+10 | | 3x+y+40=180 | | (n*9)+4=58 | | b=m-2 |