15x2+22x=-8

Solution for 15x2+22x=-8 equation:

15x^2+22x=-8

We move all terms to the left:

15x^2+22x-(-8)=0

We add all the numbers together, and all the variables

15x^2+22x+8=0

a = 15; b = 22; c = +8;
Δ = b2-4ac
Δ = 222-4·15·8
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-2}{2*15}=\frac{-24}{30}
=-4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+2}{2*15}=\frac{-20}{30}
=-2/3
$