15x2+29x+12=0

Solution for 15x2+29x+12=0 equation:

15x^2+29x+12=0

a = 15; b = 29; c = +12;
Δ = b2-4ac
Δ = 292-4·15·12
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-11}{2*15}=\frac{-40}{30}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+11}{2*15}=\frac{-18}{30}
=-3/5
$