15x2+30x-2145=0

Solution for 15x2+30x-2145=0 equation:

15x^2+30x-2145=0

a = 15; b = 30; c = -2145;
Δ = b2-4ac
Δ = 302-4·15·(-2145)
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{129600}=360$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-360}{2*15}=\frac{-390}{30}
=-13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+360}{2*15}=\frac{330}{30}
=11
$