15x2+37x-12=0

Solution for 15x2+37x-12=0 equation:

15x^2+37x-12=0

a = 15; b = 37; c = -12;
Δ = b2-4ac
Δ = 372-4·15·(-12)
Δ = 2089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{2089}}{2*15}=\frac{-37-\sqrt{2089}}{30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{2089}}{2*15}=\frac{-37+\sqrt{2089}}{30}
$