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15x^2+43x+30=0
a = 15; b = 43; c = +30;
Δ = b2-4ac
Δ = 432-4·15·30
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-7}{2*15}=\frac{-50}{30} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+7}{2*15}=\frac{-36}{30} =-1+1/5 $
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