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15x^2+59x+4=0
a = 15; b = 59; c = +4;
Δ = b2-4ac
Δ = 592-4·15·4
Δ = 3241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(59)-\sqrt{3241}}{2*15}=\frac{-59-\sqrt{3241}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(59)+\sqrt{3241}}{2*15}=\frac{-59+\sqrt{3241}}{30} $
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