15x2+59x+56=0

Solution for 15x2+59x+56=0 equation:

15x^2+59x+56=0

a = 15; b = 59; c = +56;
Δ = b2-4ac
Δ = 592-4·15·56
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(59)-11}{2*15}=\frac{-70}{30}
=-2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(59)+11}{2*15}=\frac{-48}{30}
=-1+3/5
$