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15x^2+7x=3
We move all terms to the left:
15x^2+7x-(3)=0
a = 15; b = 7; c = -3;
Δ = b2-4ac
Δ = 72-4·15·(-3)
Δ = 229
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{229}}{2*15}=\frac{-7-\sqrt{229}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{229}}{2*15}=\frac{-7+\sqrt{229}}{30} $
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