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15x^2-18x-24=0
a = 15; b = -18; c = -24;
Δ = b2-4ac
Δ = -182-4·15·(-24)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:x_{1}=\frac{-b-\sqrt{\Delta}}{2a}x_{2}=\frac{-b+\sqrt{\Delta}}{2a}\sqrt{\Delta}=\sqrt{1764}=42x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-42}{2*15}=\frac{-24}{30} =-4/5x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+42}{2*15}=\frac{60}{30} =2
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