15x2-26x+8=0

Solution for 15x2-26x+8=0 equation:

15x^2-26x+8=0

a = 15; b = -26; c = +8;
Δ = b2-4ac
Δ = -262-4·15·8
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-14}{2*15}=\frac{12}{30}
=2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+14}{2*15}=\frac{40}{30}
=1+1/3
$