15x2-26x-73=0

Solution for 15x2-26x-73=0 equation:

15x^2-26x-73=0

a = 15; b = -26; c = -73;
Δ = b2-4ac
Δ = -262-4·15·(-73)
Δ = 5056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5056}=\sqrt{64*79}=\sqrt{64}*\sqrt{79}=8\sqrt{79}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-8\sqrt{79}}{2*15}=\frac{26-8\sqrt{79}}{30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+8\sqrt{79}}{2*15}=\frac{26+8\sqrt{79}}{30}
$