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15x^2-31x-14=0
a = 15; b = -31; c = -14;
Δ = b2-4ac
Δ = -312-4·15·(-14)
Δ = 1801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-\sqrt{1801}}{2*15}=\frac{31-\sqrt{1801}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+\sqrt{1801}}{2*15}=\frac{31+\sqrt{1801}}{30} $
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