15x2-49x+26=0

Solution for 15x2-49x+26=0 equation:

15x^2-49x+26=0

a = 15; b = -49; c = +26;
Δ = b2-4ac
Δ = -492-4·15·26
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-29}{2*15}=\frac{20}{30}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+29}{2*15}=\frac{78}{30}
=2+3/5
$