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15x^2-57x-90=0
a = 15; b = -57; c = -90;
Δ = b2-4ac
Δ = -572-4·15·(-90)
Δ = 8649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8649}=93$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-93}{2*15}=\frac{-36}{30} =-1+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+93}{2*15}=\frac{150}{30} =5 $
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