15x2-7x-36=0

Solution for 15x2-7x-36=0 equation:

15x^2-7x-36=0

a = 15; b = -7; c = -36;
Δ = b2-4ac
Δ = -72-4·15·(-36)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-47}{2*15}=\frac{-40}{30}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+47}{2*15}=\frac{54}{30}
=1+4/5
$