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15x^2-7x=2
We move all terms to the left:
15x^2-7x-(2)=0
a = 15; b = -7; c = -2;
Δ = b2-4ac
Δ = -72-4·15·(-2)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-13}{2*15}=\frac{-6}{30} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+13}{2*15}=\frac{20}{30} =2/3 $
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