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15x^2-84x-36=0
a = 15; b = -84; c = -36;
Δ = b2-4ac
Δ = -842-4·15·(-36)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-84)-96}{2*15}=\frac{-12}{30} =-2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-84)+96}{2*15}=\frac{180}{30} =6 $
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