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15x^2-x-28=0
We add all the numbers together, and all the variables
15x^2-1x-28=0
a = 15; b = -1; c = -28;
Δ = b2-4ac
Δ = -12-4·15·(-28)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-41}{2*15}=\frac{-40}{30} =-1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+41}{2*15}=\frac{42}{30} =1+2/5 $
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