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15x^2=28
We move all terms to the left:
15x^2-(28)=0
a = 15; b = 0; c = -28;
Δ = b2-4ac
Δ = 02-4·15·(-28)
Δ = 1680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1680}=\sqrt{16*105}=\sqrt{16}*\sqrt{105}=4\sqrt{105}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{105}}{2*15}=\frac{0-4\sqrt{105}}{30} =-\frac{4\sqrt{105}}{30} =-\frac{2\sqrt{105}}{15} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{105}}{2*15}=\frac{0+4\sqrt{105}}{30} =\frac{4\sqrt{105}}{30} =\frac{2\sqrt{105}}{15} $
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