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15x^2=540
We move all terms to the left:
15x^2-(540)=0
a = 15; b = 0; c = -540;
Δ = b2-4ac
Δ = 02-4·15·(-540)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*15}=\frac{-180}{30} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*15}=\frac{180}{30} =6 $
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