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15x^2=x+215x^2=x+2
We move all terms to the left:
15x^2-(x+215x^2)=0
We get rid of parentheses
15x^2-215x^2-x=0
We add all the numbers together, and all the variables
-200x^2-1x=0
a = -200; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-200)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-200}=\frac{0}{-400} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-200}=\frac{2}{-400} =-1/200 $
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