15y*32=2(10y-7)-5y+46

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Solution for 15y*32=2(10y-7)-5y+46 equation: 



15y*32=2(10y-7)-5y+46

We move all terms to the left:

15y*32-(2(10y-7)-5y+46)=0

Wy multiply elements

480y-(2(10y-7)-5y+46)=0



We calculate terms in parentheses: -(2(10y-7)-5y+46), so:

2(10y-7)-5y+46

We add all the numbers together, and all the variables

-5y+2(10y-7)+46

We multiply parentheses

-5y+20y-14+46

We add all the numbers together, and all the variables

15y+32

Back to the equation:

-(15y+32)



We get rid of parentheses

480y-15y-32=0

We add all the numbers together, and all the variables

465y-32=0

We move all terms containing y to the left, all other terms to the right

465y=32

y=32/465

y=32/465

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