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15y+5=5(3y+1)
We move all terms to the left:
15y+5-(5(3y+1))=0
We calculate terms in parentheses: -(5(3y+1)), so:We get rid of parentheses
5(3y+1)
We multiply parentheses
15y+5
Back to the equation:
-(15y+5)
15y-15y-5+5=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0
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