15y-10=6y-(y+2)+(y+3)

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Solution for 15y-10=6y-(y+2)+(y+3) equation: 



15y-10=6y-(y+2)+(y+3)

We move all terms to the left:

15y-10-(6y-(y+2)+(y+3))=0



We calculate terms in parentheses: -(6y-(y+2)+(y+3)), so:

6y-(y+2)+(y+3)

We get rid of parentheses

6y-y+y-2+3

We add all the numbers together, and all the variables

6y+1

Back to the equation:

-(6y+1)



We get rid of parentheses

15y-6y-1-10=0

We add all the numbers together, and all the variables

9y-11=0

We move all terms containing y to the left, all other terms to the right

9y=11

y=11/9

y=1+2/9

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