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15y-12=3(5y-4)
We move all terms to the left:
15y-12-(3(5y-4))=0
We calculate terms in parentheses: -(3(5y-4)), so:We get rid of parentheses
3(5y-4)
We multiply parentheses
15y-12
Back to the equation:
-(15y-12)
15y-15y+12-12=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0
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