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15y-1=11/2y+2
We move all terms to the left:
15y-1-(11/2y+2)=0
Domain of the equation: 2y+2)!=0We get rid of parentheses
y∈R
15y-11/2y-2-1=0
We multiply all the terms by the denominator
15y*2y-2*2y-1*2y-11=0
Wy multiply elements
30y^2-4y-2y-11=0
We add all the numbers together, and all the variables
30y^2-6y-11=0
a = 30; b = -6; c = -11;
Δ = b2-4ac
Δ = -62-4·30·(-11)
Δ = 1356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1356}=\sqrt{4*339}=\sqrt{4}*\sqrt{339}=2\sqrt{339}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{339}}{2*30}=\frac{6-2\sqrt{339}}{60} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{339}}{2*30}=\frac{6+2\sqrt{339}}{60} $
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