15y-2(4y-2)=2(3y-1)

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Solution for 15y-2(4y-2)=2(3y-1) equation: 



15y-2(4y-2)=2(3y-1)

We move all terms to the left:

15y-2(4y-2)-(2(3y-1))=0

We multiply parentheses

15y-8y-(2(3y-1))+4=0



We calculate terms in parentheses: -(2(3y-1)), so:

2(3y-1)

We multiply parentheses

6y-2

Back to the equation:

-(6y-2)



We add all the numbers together, and all the variables

7y-(6y-2)+4=0

We get rid of parentheses

7y-6y+2+4=0

We add all the numbers together, and all the variables

y+6=0

We move all terms containing y to the left, all other terms to the right

y=-6

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