15y2-14y-49=0

Solution for 15y2-14y-49=0 equation:

15y^2-14y-49=0

a = 15; b = -14; c = -49;
Δ = b2-4ac
Δ = -142-4·15·(-49)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-56}{2*15}=\frac{-42}{30}
=-1+2/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+56}{2*15}=\frac{70}{30}
=2+1/3
$