15y=25y2+2

Solution for 15y=25y2+2 equation:

15y=25y^2+2

We move all terms to the left:

15y-(25y^2+2)=0

We get rid of parentheses

-25y^2+15y-2=0

a = -25; b = 15; c = -2;
Δ = b2-4ac
Δ = 152-4·(-25)·(-2)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-5}{2*-25}=\frac{-20}{-50}
=2/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+5}{2*-25}=\frac{-10}{-50}
=1/5
$