15z+(4-z)=9-(z-6)

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Solution for 15z+(4-z)=9-(z-6) equation: 



15z+(4-z)=9-(z-6)

We move all terms to the left:

15z+(4-z)-(9-(z-6))=0

We add all the numbers together, and all the variables

15z+(-1z+4)-(9-(z-6))=0

We get rid of parentheses

15z-1z-(9-(z-6))+4=0



We calculate terms in parentheses: -(9-(z-6)), so:

9-(z-6)

determiningTheFunctionDomain
-(z-6)+9

We get rid of parentheses

-z+6+9

We add all the numbers together, and all the variables

-1z+15

Back to the equation:

-(-1z+15)



We add all the numbers together, and all the variables

14z-(-1z+15)+4=0

We get rid of parentheses

14z+1z-15+4=0

We add all the numbers together, and all the variables

15z-11=0

We move all terms containing z to the left, all other terms to the right

15z=11

z=11/15

z=11/15

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