15z+(4z/2)=51

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Solution for 15z+(4z/2)=51 equation: 



15z+(4z/2)=51

We move all terms to the left:

15z+(4z/2)-(51)=0

We add all the numbers together, and all the variables

15z+(+4z/2)-51=0

We get rid of parentheses

15z+4z/2-51=0

We multiply all the terms by the denominator


15z*2+4z-51*2=0

We add all the numbers together, and all the variables

4z+15z*2-102=0

Wy multiply elements

4z+30z-102=0

We add all the numbers together, and all the variables

34z-102=0

We move all terms containing z to the left, all other terms to the right

34z=102

z=102/34

z=3

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