16(0.4)=s(2)

Solution for 16(0.4)=s(2) equation:

16(0.4)=s(2)

We move all terms to the left:

16(0.4)-(s(2))=0

determiningTheFunctionDomain
-s2+16(0.4)=0

We add all the numbers together, and all the variables

-1s^2+6.4=0

a = -1; b = 0; c = +6.4;
Δ = b2-4ac
Δ = 02-4·(-1)·6.4
Δ = 25.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{25.6}}{2*-1}=\frac{0-\sqrt{25.6}}{-2}
=-\frac{\sqrt{}}{-2}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{25.6}}{2*-1}=\frac{0+\sqrt{25.6}}{-2}
=\frac{\sqrt{}}{-2}
$