If it's not what You are looking for type in the equation solver your own equation and let us solve it.
Oblicz to!
16*(8*(1/2)-1) = 0
1/(216^2)-16 = 0
4*(cos((x^1)/2))^2
1;4;3;4
1-1+1+1;1-1-1-1
| 4.9t^2-10.5t-27.3=0 | | 15a+13b+2c+2c-4b-2a= | | x^2-18+48=0 | | 20p+18q+p-4q-7p= | | 3x+5=-7x+12 | | 14m+3n-6m+7n= | | 1/216^2-16 | | 16a+12b+6c+2c-2b-5a= | | 17p+20q+p-4q-7p= | | 15m+5n-5m+11n= | | Log(5x-2)+3=6 | | 12a+11b+5c+6c-4b-2a= | | 17p+20q+p-4q-4p= | | tan(a)=1.04 | | 11m+4m-3m+10n= | | 8x-3y+10x-2y-3y+7x= | | 4w+6y+6x+9x-11y+4w= | | 2x+7=25x | | 4w+7x+13y+3w+8x-8y= | | 18a+13b+6c+6c-6b-6a= | | 18p+16q+p-4q-5p= | | x=50-240-6x | | x=25-40-x | | 8m+6n-4m+11n= | | 18p+14q+p-4q-6p= | | Log(x)+1=3 | | Logx+1=3 | | 25=20logx | | y=2x-4x-1 | | (3x)(x)=5x+4 | | (15a+12b)-(2a-3b)= | | (u^3)+2u=12 |