16(1/2)5x+1-2=0

Solution for 16(1/2)5x+1-2=0 equation:

16(1/2)5x+1-2=0


Domain of the equation: 2)5x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

16(+1/2)5x+1-2=0

We add all the numbers together, and all the variables

16(+1/2)5x-1=0

We multiply parentheses

80x^2-1=0

a = 80; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·80·(-1)
Δ = 320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{320}=\sqrt{64*5}=\sqrt{64}*\sqrt{5}=8\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{5}}{2*80}=\frac{0-8\sqrt{5}}{160}
=-\frac{8\sqrt{5}}{160}
=-\frac{\sqrt{5}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{5}}{2*80}=\frac{0+8\sqrt{5}}{160}
=\frac{8\sqrt{5}}{160}
=\frac{\sqrt{5}}{20}
$