16(2*x-1)=4(x+3)+2*x

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Solution for 16(2*x-1)=4(x+3)+2*x equation: 



16(2x-1)=4(x+3)+2x

We move all terms to the left:

16(2x-1)-(4(x+3)+2x)=0

We multiply parentheses

32x-(4(x+3)+2x)-16=0



We calculate terms in parentheses: -(4(x+3)+2x), so:

4(x+3)+2x

We add all the numbers together, and all the variables

2x+4(x+3)

We multiply parentheses

2x+4x+12

We add all the numbers together, and all the variables

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

32x-6x-12-16=0

We add all the numbers together, and all the variables

26x-28=0

We move all terms containing x to the left, all other terms to the right

26x=28

x=28/26

x=1+1/13

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