16(2p+3)+21p=7(9p+2)

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Solution for 16(2p+3)+21p=7(9p+2) equation: 



16(2p+3)+21p=7(9p+2)

We move all terms to the left:

16(2p+3)+21p-(7(9p+2))=0

We add all the numbers together, and all the variables

21p+16(2p+3)-(7(9p+2))=0

We multiply parentheses

21p+32p-(7(9p+2))+48=0



We calculate terms in parentheses: -(7(9p+2)), so:

7(9p+2)

We multiply parentheses

63p+14

Back to the equation:

-(63p+14)



We add all the numbers together, and all the variables

53p-(63p+14)+48=0

We get rid of parentheses

53p-63p-14+48=0

We add all the numbers together, and all the variables

-10p+34=0

We move all terms containing p to the left, all other terms to the right

-10p=-34

p=-34/-10

p=3+2/5

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