16(2v+4)=-8(v-4)

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Solution for 16(2v+4)=-8(v-4) equation: 



16(2v+4)=-8(v-4)

We move all terms to the left:

16(2v+4)-(-8(v-4))=0

We multiply parentheses

32v-(-8(v-4))+64=0



We calculate terms in parentheses: -(-8(v-4)), so:

-8(v-4)

We multiply parentheses

-8v+32

Back to the equation:

-(-8v+32)



We get rid of parentheses

32v+8v-32+64=0

We add all the numbers together, and all the variables

40v+32=0

We move all terms containing v to the left, all other terms to the right

40v=-32

v=-32/40

v=-4/5

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