16(2x+5)=40(3x+1)+5(-x+8)

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Solution for 16(2x+5)=40(3x+1)+5(-x+8) equation: 



16(2x+5)=40(3x+1)+5(-x+8)

We move all terms to the left:

16(2x+5)-(40(3x+1)+5(-x+8))=0

We add all the numbers together, and all the variables

16(2x+5)-(40(3x+1)+5(-1x+8))=0

We multiply parentheses

32x-(40(3x+1)+5(-1x+8))+80=0



We calculate terms in parentheses: -(40(3x+1)+5(-1x+8)), so:

40(3x+1)+5(-1x+8)

We multiply parentheses

120x-5x+40+40

We add all the numbers together, and all the variables

115x+80

Back to the equation:

-(115x+80)



We get rid of parentheses

32x-115x-80+80=0

We add all the numbers together, and all the variables

-83x=0

x=0/-83

x=0

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