16(2x-0)=32

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Solution for 16(2x-0)=32 equation: 



16(2x-0)=32

We move all terms to the left:

16(2x-0)-(32)=0

We add all the numbers together, and all the variables

16(+2x)-32=0

We multiply parentheses

32x-32=0

We move all terms containing x to the left, all other terms to the right

32x=32

x=32/32

x=1

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